3.417 \(\int \frac{1}{(a+b \log (c (d (e+f x)^m)^n))^{7/2}} \, dx\)

Optimal. Leaf size=237 \[ \frac{8 \sqrt{\pi } (e+f x) e^{-\frac{a}{b m n}} \left (c \left (d (e+f x)^m\right )^n\right )^{-\frac{1}{m n}} \text{Erfi}\left (\frac{\sqrt{a+b \log \left (c \left (d (e+f x)^m\right )^n\right )}}{\sqrt{b} \sqrt{m} \sqrt{n}}\right )}{15 b^{7/2} f m^{7/2} n^{7/2}}-\frac{8 (e+f x)}{15 b^3 f m^3 n^3 \sqrt{a+b \log \left (c \left (d (e+f x)^m\right )^n\right )}}-\frac{4 (e+f x)}{15 b^2 f m^2 n^2 \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{3/2}}-\frac{2 (e+f x)}{5 b f m n \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{5/2}} \]

[Out]

(8*Sqrt[Pi]*(e + f*x)*Erfi[Sqrt[a + b*Log[c*(d*(e + f*x)^m)^n]]/(Sqrt[b]*Sqrt[m]*Sqrt[n])])/(15*b^(7/2)*E^(a/(
b*m*n))*f*m^(7/2)*n^(7/2)*(c*(d*(e + f*x)^m)^n)^(1/(m*n))) - (2*(e + f*x))/(5*b*f*m*n*(a + b*Log[c*(d*(e + f*x
)^m)^n])^(5/2)) - (4*(e + f*x))/(15*b^2*f*m^2*n^2*(a + b*Log[c*(d*(e + f*x)^m)^n])^(3/2)) - (8*(e + f*x))/(15*
b^3*f*m^3*n^3*Sqrt[a + b*Log[c*(d*(e + f*x)^m)^n]])

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Rubi [A]  time = 0.384623, antiderivative size = 237, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.273, Rules used = {2389, 2297, 2300, 2180, 2204, 2445} \[ \frac{8 \sqrt{\pi } (e+f x) e^{-\frac{a}{b m n}} \left (c \left (d (e+f x)^m\right )^n\right )^{-\frac{1}{m n}} \text{Erfi}\left (\frac{\sqrt{a+b \log \left (c \left (d (e+f x)^m\right )^n\right )}}{\sqrt{b} \sqrt{m} \sqrt{n}}\right )}{15 b^{7/2} f m^{7/2} n^{7/2}}-\frac{8 (e+f x)}{15 b^3 f m^3 n^3 \sqrt{a+b \log \left (c \left (d (e+f x)^m\right )^n\right )}}-\frac{4 (e+f x)}{15 b^2 f m^2 n^2 \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{3/2}}-\frac{2 (e+f x)}{5 b f m n \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{5/2}} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*Log[c*(d*(e + f*x)^m)^n])^(-7/2),x]

[Out]

(8*Sqrt[Pi]*(e + f*x)*Erfi[Sqrt[a + b*Log[c*(d*(e + f*x)^m)^n]]/(Sqrt[b]*Sqrt[m]*Sqrt[n])])/(15*b^(7/2)*E^(a/(
b*m*n))*f*m^(7/2)*n^(7/2)*(c*(d*(e + f*x)^m)^n)^(1/(m*n))) - (2*(e + f*x))/(5*b*f*m*n*(a + b*Log[c*(d*(e + f*x
)^m)^n])^(5/2)) - (4*(e + f*x))/(15*b^2*f*m^2*n^2*(a + b*Log[c*(d*(e + f*x)^m)^n])^(3/2)) - (8*(e + f*x))/(15*
b^3*f*m^3*n^3*Sqrt[a + b*Log[c*(d*(e + f*x)^m)^n]])

Rule 2389

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.), x_Symbol] :> Dist[1/e, Subst[Int[(a + b*Log[c*
x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, n, p}, x]

Rule 2297

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_), x_Symbol] :> Simp[(x*(a + b*Log[c*x^n])^(p + 1))/(b*n*(p + 1))
, x] - Dist[1/(b*n*(p + 1)), Int[(a + b*Log[c*x^n])^(p + 1), x], x] /; FreeQ[{a, b, c, n}, x] && LtQ[p, -1] &&
IntegerQ[2*p]

Rule 2300

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_), x_Symbol] :> Dist[x/(n*(c*x^n)^(1/n)), Subst[Int[E^(x/n)*(a +
b*x)^p, x], x, Log[c*x^n]], x] /; FreeQ[{a, b, c, n, p}, x]

Rule 2180

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[F^(g*(e - (c*
f)/d) + (f*g*x^2)/d), x], x, Sqrt[c + d*x]], x] /; FreeQ[{F, c, d, e, f, g}, x] &&  !$UseGamma === True

Rule 2204

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erfi[(c + d*x)*Rt[b*Log[F], 2
]])/(2*d*Rt[b*Log[F], 2]), x] /; FreeQ[{F, a, b, c, d}, x] && PosQ[b]

Rule 2445

Int[((a_.) + Log[(c_.)*((d_.)*((e_.) + (f_.)*(x_))^(m_.))^(n_)]*(b_.))^(p_.)*(u_.), x_Symbol] :> Subst[Int[u*(
a + b*Log[c*d^n*(e + f*x)^(m*n)])^p, x], c*d^n*(e + f*x)^(m*n), c*(d*(e + f*x)^m)^n] /; FreeQ[{a, b, c, d, e,
f, m, n, p}, x] &&  !IntegerQ[n] &&  !(EqQ[d, 1] && EqQ[m, 1]) && IntegralFreeQ[IntHide[u*(a + b*Log[c*d^n*(e
+ f*x)^(m*n)])^p, x]]

Rubi steps

\begin{align*} \int \frac{1}{\left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{7/2}} \, dx &=\operatorname{Subst}\left (\int \frac{1}{\left (a+b \log \left (c d^n (e+f x)^{m n}\right )\right )^{7/2}} \, dx,c d^n (e+f x)^{m n},c \left (d (e+f x)^m\right )^n\right )\\ &=\operatorname{Subst}\left (\frac{\operatorname{Subst}\left (\int \frac{1}{\left (a+b \log \left (c d^n x^{m n}\right )\right )^{7/2}} \, dx,x,e+f x\right )}{f},c d^n (e+f x)^{m n},c \left (d (e+f x)^m\right )^n\right )\\ &=-\frac{2 (e+f x)}{5 b f m n \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{5/2}}+\operatorname{Subst}\left (\frac{2 \operatorname{Subst}\left (\int \frac{1}{\left (a+b \log \left (c d^n x^{m n}\right )\right )^{5/2}} \, dx,x,e+f x\right )}{5 b f m n},c d^n (e+f x)^{m n},c \left (d (e+f x)^m\right )^n\right )\\ &=-\frac{2 (e+f x)}{5 b f m n \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{5/2}}-\frac{4 (e+f x)}{15 b^2 f m^2 n^2 \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{3/2}}+\operatorname{Subst}\left (\frac{4 \operatorname{Subst}\left (\int \frac{1}{\left (a+b \log \left (c d^n x^{m n}\right )\right )^{3/2}} \, dx,x,e+f x\right )}{15 b^2 f m^2 n^2},c d^n (e+f x)^{m n},c \left (d (e+f x)^m\right )^n\right )\\ &=-\frac{2 (e+f x)}{5 b f m n \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{5/2}}-\frac{4 (e+f x)}{15 b^2 f m^2 n^2 \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{3/2}}-\frac{8 (e+f x)}{15 b^3 f m^3 n^3 \sqrt{a+b \log \left (c \left (d (e+f x)^m\right )^n\right )}}+\operatorname{Subst}\left (\frac{8 \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b \log \left (c d^n x^{m n}\right )}} \, dx,x,e+f x\right )}{15 b^3 f m^3 n^3},c d^n (e+f x)^{m n},c \left (d (e+f x)^m\right )^n\right )\\ &=-\frac{2 (e+f x)}{5 b f m n \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{5/2}}-\frac{4 (e+f x)}{15 b^2 f m^2 n^2 \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{3/2}}-\frac{8 (e+f x)}{15 b^3 f m^3 n^3 \sqrt{a+b \log \left (c \left (d (e+f x)^m\right )^n\right )}}+\operatorname{Subst}\left (\frac{\left (8 (e+f x) \left (c d^n (e+f x)^{m n}\right )^{-\frac{1}{m n}}\right ) \operatorname{Subst}\left (\int \frac{e^{\frac{x}{m n}}}{\sqrt{a+b x}} \, dx,x,\log \left (c d^n (e+f x)^{m n}\right )\right )}{15 b^3 f m^4 n^4},c d^n (e+f x)^{m n},c \left (d (e+f x)^m\right )^n\right )\\ &=-\frac{2 (e+f x)}{5 b f m n \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{5/2}}-\frac{4 (e+f x)}{15 b^2 f m^2 n^2 \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{3/2}}-\frac{8 (e+f x)}{15 b^3 f m^3 n^3 \sqrt{a+b \log \left (c \left (d (e+f x)^m\right )^n\right )}}+\operatorname{Subst}\left (\frac{\left (16 (e+f x) \left (c d^n (e+f x)^{m n}\right )^{-\frac{1}{m n}}\right ) \operatorname{Subst}\left (\int e^{-\frac{a}{b m n}+\frac{x^2}{b m n}} \, dx,x,\sqrt{a+b \log \left (c d^n (e+f x)^{m n}\right )}\right )}{15 b^4 f m^4 n^4},c d^n (e+f x)^{m n},c \left (d (e+f x)^m\right )^n\right )\\ &=\frac{8 e^{-\frac{a}{b m n}} \sqrt{\pi } (e+f x) \left (c \left (d (e+f x)^m\right )^n\right )^{-\frac{1}{m n}} \text{erfi}\left (\frac{\sqrt{a+b \log \left (c \left (d (e+f x)^m\right )^n\right )}}{\sqrt{b} \sqrt{m} \sqrt{n}}\right )}{15 b^{7/2} f m^{7/2} n^{7/2}}-\frac{2 (e+f x)}{5 b f m n \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{5/2}}-\frac{4 (e+f x)}{15 b^2 f m^2 n^2 \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{3/2}}-\frac{8 (e+f x)}{15 b^3 f m^3 n^3 \sqrt{a+b \log \left (c \left (d (e+f x)^m\right )^n\right )}}\\ \end{align*}

Mathematica [A]  time = 0.420498, size = 272, normalized size = 1.15 \[ -\frac{2 (e+f x) e^{-\frac{a}{b m n}} \left (c \left (d (e+f x)^m\right )^n\right )^{-\frac{1}{m n}} \left (e^{\frac{a}{b m n}} \left (c \left (d (e+f x)^m\right )^n\right )^{\frac{1}{m n}} \left (4 a^2+2 b (4 a+b m n) \log \left (c \left (d (e+f x)^m\right )^n\right )+2 a b m n+4 b^2 \log ^2\left (c \left (d (e+f x)^m\right )^n\right )+3 b^2 m^2 n^2\right )-4 \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^2 \sqrt{-\frac{a+b \log \left (c \left (d (e+f x)^m\right )^n\right )}{b m n}} \text{Gamma}\left (\frac{1}{2},-\frac{a+b \log \left (c \left (d (e+f x)^m\right )^n\right )}{b m n}\right )\right )}{15 b^3 f m^3 n^3 \left (a+b \log \left (c \left (d (e+f x)^m\right )^n\right )\right )^{5/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*Log[c*(d*(e + f*x)^m)^n])^(-7/2),x]

[Out]

(-2*(e + f*x)*(-4*Gamma[1/2, -((a + b*Log[c*(d*(e + f*x)^m)^n])/(b*m*n))]*(a + b*Log[c*(d*(e + f*x)^m)^n])^2*S
qrt[-((a + b*Log[c*(d*(e + f*x)^m)^n])/(b*m*n))] + E^(a/(b*m*n))*(c*(d*(e + f*x)^m)^n)^(1/(m*n))*(4*a^2 + 2*a*
b*m*n + 3*b^2*m^2*n^2 + 2*b*(4*a + b*m*n)*Log[c*(d*(e + f*x)^m)^n] + 4*b^2*Log[c*(d*(e + f*x)^m)^n]^2)))/(15*b
^3*E^(a/(b*m*n))*f*m^3*n^3*(c*(d*(e + f*x)^m)^n)^(1/(m*n))*(a + b*Log[c*(d*(e + f*x)^m)^n])^(5/2))

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Maple [F]  time = 0.554, size = 0, normalized size = 0. \begin{align*} \int \left ( a+b\ln \left ( c \left ( d \left ( fx+e \right ) ^{m} \right ) ^{n} \right ) \right ) ^{-{\frac{7}{2}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a+b*ln(c*(d*(f*x+e)^m)^n))^(7/2),x)

[Out]

int(1/(a+b*ln(c*(d*(f*x+e)^m)^n))^(7/2),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b \log \left (\left ({\left (f x + e\right )}^{m} d\right )^{n} c\right ) + a\right )}^{\frac{7}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*log(c*(d*(f*x+e)^m)^n))^(7/2),x, algorithm="maxima")

[Out]

integrate((b*log(((f*x + e)^m*d)^n*c) + a)^(-7/2), x)

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Fricas [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*log(c*(d*(f*x+e)^m)^n))^(7/2),x, algorithm="fricas")

[Out]

Exception raised: UnboundLocalError

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*ln(c*(d*(f*x+e)**m)**n))**(7/2),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b \log \left (\left ({\left (f x + e\right )}^{m} d\right )^{n} c\right ) + a\right )}^{\frac{7}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*log(c*(d*(f*x+e)^m)^n))^(7/2),x, algorithm="giac")

[Out]

integrate((b*log(((f*x + e)^m*d)^n*c) + a)^(-7/2), x)